Php return error in json

$ con) { die( " Connection failed: ". mysqli_ connect_ error. I showed how you can return JSON response and. An article on how to do error handling with json_ encode and json_ decode. I want to return JSON from a PHP script. Do I just echo the result? Do I have to set the Content- Type header? throw new \ LogicException( sprintf( " Failed to parse json string ' % s', error: ' % s' ", $ this- > data, $ error) ) ; } / / in php 5. switch ( json_ last_ error( ) ) { default: return; case JSON_ ERROR_ DEPTH: $ error = ' Maximum stack depth exceeded' ; turn value for json_ encode( ) on failure not listed:. w+ ' ) ) ) ; " PHP Warning: json. cases" or possibly something mentioning the null return.

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  • Video:Return error json

    Return error json

    How to encode and decode JSON in PHP? json_ last_ error( ) sometimes doesn' t return the last error, but the last- but- one error. You could take this approach, and just return the error and exception details if an exception is thrown: